b^=-35+12b

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Solution for b^=-35+12b equation: 



b^=-35+12b

We move all terms to the left:

b^-(-35+12b)=0

We add all the numbers together, and all the variables

b^-(12b-35)=0

We add all the numbers together, and all the variables

b-(12b-35)=0

We get rid of parentheses

b-12b+35=0

We add all the numbers together, and all the variables

-11b+35=0

We move all terms containing b to the left, all other terms to the right

-11b=-35

b=-35/-11

b=3+2/11

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